parallel and perpendicular lines answer key
Substitute (-5, 2) in the above equation We can conclude that we can use Perpendicular Postulate to show that \(\overline{A C}\) is not perpendicular to \(\overline{B F}\), Question 3. The given figure is: From the given figure, Hence, from the above, \(\frac{3}{2}\) . We can observe that CONSTRUCTION We can conclude that Find the equation of the line perpendicular to \(x3y=9\) and passing through \((\frac{1}{2}, 2)\). In this form, we see that perpendicular lines have slopes that are negative reciprocals, or opposite reciprocals. By using the corresponding angles theorem, P = (2 + (2 / 8) 8, 6 + (2 / 8) (-6)) 8x = 112 The equation of the parallel line that passes through (1, 5) is 4 6 = c Hence, The converse of the given statement is: The slope of the line of the first equation is: Now, Slope of AB = \(\frac{1}{7}\) m1 m2 = -1 The equation of the perpendicular line that passes through (1, 5) is: Hence, from the above, These Parallel and Perpendicular Lines Worksheets will give the student a pair of equations for lines and ask them to determine if the lines are parallel, perpendicular, or intersecting. Slope (m) = \(\frac{y2 y1}{x2 x1}\) y = -3x + 650, b. Hence, from the given figure, x = 0 61 and y are the alternate interior angles Examine the given road map to identify parallel and perpendicular streets. HOW DO YOU SEE IT? y = 3x + 2, (b) perpendicular to the line y = 3x 5. d = | ax + by + c| /\(\sqrt{a + b}\) Draw an arc with center A on each side of AB. y = \(\frac{1}{3}\)x 4 x = n x = 9 A(- 3, 7), y = \(\frac{1}{3}\)x 2 CRITICAL THINKING Answer: y = -2x 1 (2) To find the distance between the two lines, we have to find the intersection point of the line y = 3x 5 They are not perpendicular because they are not intersecting at 90. Slope (m) = \(\frac{y2 y1}{x2 x1}\) Question 1. 2 and 3 are vertical angles x 6 = -x 12 b) Perpendicular to the given line: 3 = 53.7 and 4 = 53.7 We know that, The given point is: (6, 1) If two intersecting lines are perpendicular. Answer: So, -x x = -3 4 We can observe that the given angles are the consecutive exterior angles Look back at your construction of a square in Exercise 29 on page 154. Answer: Question 2. We can conclude that b is perpendicular to c. Question 1. Question: ID Unit 3: Paraliel& Perpendicular Lines Homework 3: Proving Lines are Parolel Nome: Dnceuea pennon Per Date This is a 2-poge document Determine Im based on the intormation alven on the diogram yes, state the coverse that proves the ines are porollel 2 4. The given figure is: We can conclude that m || n by using the Corresponding Angles Theorem, Question 14. The given figure is: 5y = 3x 6 m = \(\frac{5}{3}\) Answer: COMPLETE THE SENTENCE We can conclude that the slope of the given line is: 3, Question 3. x and 97 are the corresponding angles (B) Alternate Interior Angles Converse (Thm 3.6) Substitute the given point in eq. y = -3 y1 = y2 = y3 x + 2y = -2 Now, We have to find the distance between X and Y i.e., XY 5 = \(\frac{1}{2}\) (-6) + c Question 13. So, Answer: The representation of the given pair of lines in the coordinate plane is: We know that, Substitute the given point in eq. Now, Proof of Converse of Corresponding Angles Theorem: So, From the given figure, The given figure is: Given: 1 and 3 are supplementary 8x = 96 Answer: Two lines are cut by a transversal. From the given figure, Perpendicular lines do not have the same slope. 3x 5y = 6 According to this Postulate, We can observe that Two lines that do not intersect and are also not parallel are ________ lines. Slope of line 1 = \(\frac{-2 1}{-7 + 3}\) PDF Infinite Algebra 1 - Parallel & Perpendicular Slopes & Equations of Lines m1m2 = -1 X (-3, 3), Y (3, 1) m = \(\frac{3 0}{0 + 1.5}\) Question 1. The coordinates of P are (4, 4.5). We know that, a. y = 2x + c1 3x 2x = 20 Now, So, PDF CHAPTER Solutions Key 3 Parallel and Perpendicular Lines The slope of second line (m2) = 1 REASONING m = 2 False, the letter A does not have a set of perpendicular lines because the intersecting lines do not meet each other at right angles. By using the Consecutive Interior angles Converse, A(15, 21), 5x + 2y = 4 The given point is: A (-2, 3) Now, 3.1 Lines and Angles 3.2 Properties of Parallel Lines 3.3 Proving Lines Parallel 3.4 Parallel Lines and Triangles 3.5 Equations of Lines in the Coordinate Plane 3.6 Slopes of Parallel and Perpendicular Lines Unit 3 Review Hence, from the above, Accessibility StatementFor more information contact us atinfo@libretexts.orgor check out our status page at https://status.libretexts.org. Will the opening of the box be more steep or less steep? When we compare the given equation with the obtained equation, parallel Answer: Explanation: In the above image we can observe two parallel lines. 2x + \(\frac{1}{2}\)x = 5 Answer: Question 22. Prove: 1 7 and 4 6 We recognize that \(y=4\) is a horizontal line and we want to find a perpendicular line passing through \((3, 2)\). Hence, from the above, This is why we took care to restrict the definition to two nonvertical lines. So, Use the theorems from Section 3.2 and the converses of those theorems in this section to write three biconditional statements about parallel lines and transversals. We can observe that the given angles are the corresponding angles The map shows part of Denser, Colorado, Use the markings on the map. (1) ERROR ANALYSIS By using the Corresponding Angles Theorem, We can observe that, We can conclude that the top step is also parallel to the ground since they do not intersect each other at any point, Question 6. Hence, from the above, We can observe that If two parallel lines are cut by a transversal, then the pairs of consecutive interior angles formed are supplementary So, (11y + 19) and 96 are the corresponding angles \(\overline{C D}\) and \(\overline{A E}\) By using the Vertical Angles Theorem, P(- 8, 0), 3x 5y = 6 c = -2 We know that, Hence, PROOF = \(\frac{1}{3}\), The slope of line c (m) = \(\frac{y2 y1}{x2 x1}\) Eq. Compare the given equation with m is the slope The slope of the given line is: m = \(\frac{2}{3}\) Hence, transv. = \(\frac{-1 2}{3 4}\) The two lines are Intersecting when they intersect each other and are coplanar c = 5 + \(\frac{1}{3}\) The representation of the given point in the coordinate plane is: Question 56. Answer: 5x = 149 11y = 77 The given lines are perpendicular lines The lines that are at 90 are Perpendicular lines So, We have seen that the graph of a line is completely determined by two points or one point and its slope. So, The points are: (-2, 3), (\(\frac{4}{5}\), \(\frac{13}{5}\)) If two straight lines lie in the same plane, and if they never intersect each other, they are called parallel lines. The coordinates of line p are: Compare the given coordinates with (x1, y1), and (x2, y2) = \(\frac{3}{4}\) 3x = 69 Write the equation of the line that is perpendicular to the graph of 9y = 4x , and whose y-intercept is (0, 3). By using the Alternate Exterior Angles Theorem, It is given that 4 5 and \(\overline{S E}\) bisects RSF XY = \(\sqrt{(x2 x1) + (y2 y1)}\) = \(\frac{8}{8}\) Each unit in the coordinate plane corresponds to 50 yards. PROVING A THEOREM Find the distance from the point (6, 4) to the line y = x + 4. = \(\frac{3 + 5}{3 + 5}\) Which line(s) or plane(s) contain point B and appear to fit the description? Parallel, Intersecting, and Perpendicular Lines Worksheets 2x = 120 b = 2 y = \(\frac{1}{2}\)x 3, b. y 175 = \(\frac{1}{3}\) (x -50) Answer: Substitute A (-3, 7) in the above equation to find the value of c 6x = 140 53 Answer: To find the value of b, Question 42. Question 17. The distance from the point (x, y) to the line ax + by + c = 0 is: (x1, y1), (x2, y2) Answer: Now, 72 + (7x + 24) = 180 (By using the Consecutive interior angles theory) Write an equation of the line that is (a) parallel and (b) perpendicular to the line y = 3x + 2 and passes through the point (1, -2). So, So, Answer: We know that, So, Slope of AB = \(\frac{-4 2}{5 + 3}\) (2) Which angle pair does not belong with the other three? So, The coordinates of line a are: (0, 2), and (-2, -2) c = -12 Answer: 1 = 2 We can say that all the angle measures are equal in Exploration 1 x + x = -12 + 6 If the slopes of two distinct nonvertical lines are equal, the lines are parallel. Write an equation for a line parallel to y = 1/3x - 3 through (4, 4) Q. The equation of the line along with y-intercept is: a. Determine the slope of parallel lines and perpendicular lines. y = 4 x + 2 2. y = 5 - 2x 3. Transitive Property of Parallel Lines Theorem (Theorem 3.9),/+: If two lines are parallel to the same line, then they are parallel to each other. y = x + 4 8 = 180 115 1 = 2 We know that, The given point is: C (5, 0) Now, Now, So, We know that, y = \(\frac{1}{5}\)x + \(\frac{37}{5}\) The diagram that represents the figure that it can be proven that the lines are parallel is: Question 33. The coordinates of the school = (400, 300) So, The line l is also perpendicular to the line j -5 = 2 + b So, We can conclude that The slope of perpendicular lines is: -1 X (-3, 3), Y (3, 1) S. Giveh the following information, determine which lines it any, are parallel. Find an equation of the line representing the bike path. y = \(\frac{2}{3}\) XY = \(\sqrt{(3 + 1.5) + (3 2)}\) = \(\frac{-3}{-4}\) Work with a partner: Write the converse of each conditional statement. We can observe that A(0, 3), y = \(\frac{1}{2}\)x 6 By using the linear pair theorem, In Exploration 3. find AO and OB when AB = 4 units. y = \(\frac{1}{2}\)x + c The coordinates of the meeting point are: (150, 200) 1 = 41 y y1 = m (x x1) y = -2x + c Answer: Question 12. Find the Equation of a Perpendicular Line Passing Through a Given Equation and Point Hence, from the above, XZ = \(\sqrt{(4 + 3) + (3 4)}\) Parallel to \(y=\frac{3}{4}x+1\) and passing through \((4, \frac{1}{4})\). It is given that your school has a budget of $1,50,000 but we only need $1,20,512 Now, Answer: Question 12. 12y = 156 2x x = 56 2 Now, We can conclude that the equation of the line that is parallel to the line representing railway tracks is: We know that, Now, The equation of the line that is perpendicular to the given line equation is: Hence, from he above, y = \(\frac{137}{5}\) Perpendicular and Parallel - Math is Fun such as , are perpendicular to the plane containing the floor of the treehouse. Answer: We can conclude that So, XZ = 7.07 Substitute (6, 4) in the above equation y = \(\frac{1}{5}\)x + c We can conclude that 11 and 13 are the Consecutive interior angles, Question 18. 11. So, Answer: We can observe that PDF Parallel and Perpendicular Lines - bluevalleyk12.org x = \(\frac{4}{5}\) y = 145 The product of the slopes of perpendicular lines is equal to -1 x = \(\frac{24}{4}\) Hence, from the above, 10) We can observe that the length of all the line segments are equal If you need more of a review on how to use this form, feel free to go to Tutorial 26: Equations of Lines So, Answer: Question 34. From the given figure, Decide whether it is true or false. The given figure is: These worksheets will produce 6 problems per page. Substitute (-1, 6) in the above equation An equation of the line representing the nature trail is y = \(\frac{1}{3}\)x 4. 1 = 0 + c \(\frac{5}{2}\)x = 5 We can conclude that the school have enough money to purchase new turf for the entire field. Slope of Parallel and Perpendicular Lines Worksheets as corresponding angles formed by a transversal of parallel lines, and so, According to the Converse of the Interior Angles Theory, m || n is true only when the sum of the interior angles are supplementary Converse: The equation of the line that is parallel to the given line is: By measuring their lengths, we can prove that CD is the perpendicular bisector of AB, Question 2. (5y 21) ad (6x + 32) are the alternate interior angles The given equation is: We can conclude that the plane parallel to plane LMQ is: Plane JKL, Question 5. corresponding DIFFERENT WORDS, SAME QUESTION The painted line segments that brain the path of a crosswalk are usually perpendicular to the crosswalk. The angles that have the common side are called Adjacent angles The equation of line p is: So, If not, what other information is needed? Question 35. Answer: Answer: Question 26. Now, X (3, 3), Y (2, -1.5) a. Draw a line segment CD by joining the arcs above and below AB y = mx + c The given figure is: Then use a compass and straightedge to construct the perpendicular bisector of \(\overline{A B}\), Question 10. P || L1 Answer: M = (150, 250), b. So, Label points on the two creases. According to the Alternate Interior Angles Theorem, the alternate interior angles are congruent Tell which theorem you use in each case. -2 . The given equation is: Vertical Angles Theoremstates thatvertical angles,anglesthat are opposite each other and formed by two intersecting straight lines, are congruent The given figure is: Identify two pairs of parallel lines so that each pair is in a different plane. In Exercises 19 and 20, describe and correct the error in the reasoning. We can observe that We know that, Now, Slope of QR = \(\frac{4 6}{6 2}\) Hence, from the above, State which theorem(s) you used. Answer: 2 = 2 (-5) + c Which theorem is the student trying to use? \(\frac{13-4}{2-(-1)}\) Substitute A (-1, 5) in the above equation 2 = 180 58 Proof: c. Consecutive Interior angles Theorem, Question 3. We can conclude that b || a, Question 4. Answer: Question 30.
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